Contribution per pair (fixed overhead absorbed is excluded because total fixed costs do not change): Executive Oxford 185,000 − 60,000 − 18,000 − 18,000 − 7,000 = Shs 82,000; Safari Boot 240,000 − 96,000 − 22,000 − 27,000 − 10,500 = Shs 84,500; School Shoe 96,000 − 36,000 − 10,000 − 9,000 − 3,500 = Shs 37,500.
Which resource binds? Leather needed for maximum demand = 3,000 × 2.5 + 2,500 × 4.0 + 6,000 × 1.5 = 7,500 + 10,000 + 9,000 = 26,500 square feet against 22,000 available, so leather is short. Stitching hours needed for maximum demand = 6,000 + 7,500 + 6,000 = 19,500 hours against 18,000, so stitching also looks short. Rank on leather first and then test the plan against stitching hours.
Contribution per square foot of leather: Executive Oxford 82,000 / 2.5 = Shs 32,800; School Shoe 37,500 / 1.5 = Shs 25,000; Safari Boot 84,500 / 4.0 = Shs 21,125. Executive Oxford is ranked first, School Shoe second and Safari Boot third, even though the Safari Boot earns the highest contribution per pair.
Allocation of 22,000 square feet: the contractual 1,000 School Shoes come first (1,500 sq ft), leaving 20,500. Executive Oxford 3,000 pairs use 7,500 (leaving 13,000). The remaining 5,000 School Shoes use 7,500 (leaving 5,500). Safari Boot gets 5,500 / 4.0 = 1,375 pairs.
Stitching check: 3,000 × 2 + 6,000 × 1 + 1,375 × 3 = 6,000 + 6,000 + 4,125 = 16,125 hours, within the 18,000 available, leaving 1,875 hours slack. Stitching is therefore not binding at this plan, and the single-constraint ranking gives the optimum.
| Product |
Pairs |
Contribution (Shs) |
| Executive Oxford |
3,000 |
246,000,000 |
| School Shoe (incl. contract) |
6,000 |
225,000,000 |
| Safari Boot |
1,375 |
116,187,500 |
| Total contribution |
|
587,187,500 |
| Less fixed costs |
|
(395,000,000) |
| Profit |
|
192,187,500 |
The maximum monthly profit is Shs 192,187,500, with 1,125 pairs of Safari Boot demand left unmet.
📋 Objective: 3.4 (Applying relevant cost analysis to decisions)